The sky's the limit! (Quickort on posets.) (III)

["Marko Riedel" <mriedel@xxxxxxxxxxxxx>]

Hi folks,

one more thing: suppose we are working with

    n/3-(n/9, n/9, n/9)-n/3

-- we'd have to set up recurrences for n = 0, 1, 2 ... 8 (9), which is
more complicated than it needs to be. Analyse

    3m-(m, m, m)-3m

instead. The same goes for

    (sqrt(n), sqrt(n))-(n-2sqrt(n))

Use

    (m, m)-m^2

instead.

Etc. etc.

Best regards,

-- 
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| Marko Riedel, EDV Neue Arbeit gGmbH, mriedel@neuearbeit.de |
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